Game Development Reference
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long index = nextEdge[edgeIndex];
if (index == 0xFFFF)
break ;
// Second pass over all triangles. This finds all the edges satisfying
// the condition that the first vertex index is greater than the second
// vertex index when the direction from the first vertex to the second
// vertex represents a counterclockwise winding around the triangle to
// which the edge belongs. For each of these edges, the same edge should
// have already been found in the first pass for a different triangle.
// So we search the list of edges for the higher-numbered vertex index
// for the matching edge and fill in the second triangle index. The
// maximum number of comparisons in this search for any vertex is the
// number of edges having that vertex as an endpoint.
triangle = triangleArray;
for ( long a = 0; a < triangleCount; a++)
long i1 = triangle->index[2];
for ( long b = 0; b < 3; b++)
long i2 = triangle->index[b];
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